Chromatic aberration and its reduction
Aberration
- The spherical surfaces and lenses are used to create the images of given objects.
- If we find the position, size and forms of images by using simple equations, then there will be several defects or aberration in images.
- The defects in images formed by a lens or combination of lenses are known as aberration.
![](https://sacademy.co.in/wp-content/uploads/2023/06/classification-of-aberration.jpg)
Chromatic aberration or Colour defect
- When white light incident on a prism, then after refraction form the prism it splits into seven colours.
- In the same way if white light incident on a lens and after refraction from the lens, we get the images of different colours, then such defect of lens is known as chromatic aberration or colour defect.
- Because a lens can be assumed as a combination of several prisms, and their angle of refraction decreases as we go from centre to the corner.
Reason
- The refractive index of lens material is different for different colours or the light of different wavelengths.
- The light of different wavelengths focuses at different and forms the image at different positions.
- From Cauchy relation µ = A + B/λ2
∵ λR > λV ⇒ µR < µV
∵ f ∝ 1/µ ⇒ fR > fV
- Since the focal length of red is highest, so the deviation of red is minimum and the deviation of violet is maximum.
![](https://sacademy.co.in/wp-content/uploads/2023/06/longitudinal-chromatic-aberration.jpg)
- (fr ー fv) measures the axial or longitudinal chromatic aberration.
Longitudinal chromatic aberration
- The difference of focal length of lens for red and violet colour provides the measure of axial or longitudinal chromatic aberration.
- Since focal length of lens
- But dispersive power of lens material is ω , so
- If fy = focal length of mean colour, then fy² = fv fr
- fr − fv = ωfy
- Thus longitudinal chromatic aberration is the product of dispersive power and focal length of ray of mean colour.
Transverse chromatic aberration
- If a white light object is placed normal to the axis of a lens then it is imaged normal to the axis.
- Since the refractive index of lens is different for different colours and hence the image formed normal to the axis will be of different colours and of different sizes.
- If I = size of image, O = size of object, u = distance of object from the optical centre of lens and v = distance of image from the optical centre of lens, then
- Magnification m = I/O = v/u
![](https://sacademy.co.in/wp-content/uploads/2023/06/transverse-chromatic-aberration.jpg)
Here
- AB = White object
- AvBv = Violet colour image of given white object
- ArBr = Red colour image of given white object
- ArBr ー AvBv = Measure of transverse chromatic aberration
- Mr ー Mv = Transverse chromatic aberration in terms of magnification
- If the size of red image is greater than the size of violet image (Mr > Mv), then the transverse chromatic aberration is said to be positive (aberration due to convex lens).
- If Mr < Mv, then the transverse chromatic aberration is said to be negative (aberration due to concave lens).
Analytically
- The rate of change of size of image with respect to the wavelength is chromatic aberration.
- If x = axial distance, and y = transverse distance, then
- Longitudinal chromatic aberration = dx/dλ
- Transverse chromatic aberration = dy/dλ
Achromatic lens or Achromatism
- The process of minimizing chromatic aberration is known as achromatism.
- There are two methods for getting achromatism
- By an achromatic doublet in which two lenses convex (crown glass) and concave (flint glass) are placed in contact.
- By placing two convex lenses of same material at a suitable distance.
Achromatic combination of two lenses in contact
- The combination of two or more lenses are arranged in such a way that the image obtained from it is free from chromatic aberration is achromatic lens.
- For convex lens fv < fr and for concave lens fv > fr
- Chromatic aberration of convex lens is positive.
- Chromatic aberration of concave lens is negative.
- To obtain the image free from chromatic aberration, the two lenses (one is convex and another is concave) are grouped together. Such arrangement is known as achromatic doublet.
- For achromatic doublet, we use a crown glass of high power (or low focal length) and a flint glass of low power (or large focal length).
- The focal length of two lenses are so adjusted that the focus of violet coincides with the focus of red.
![](https://sacademy.co.in/wp-content/uploads/2023/06/achromatism.jpg)
- Since focal length of thin lens is
- Let f1 and f2 be the focal length of crown and flint glass respectively, then the focal length of combination will be
- For achromatism F = constant ⇒ dF = 0
- Since ω1 / ω2 = ー f1 / f2
- And ω1 and ω2 both are positive, so f1 and f2 must be of opposite sign. It means if one lens is convex, the other lens must be concave.
- If ω1 = ω2, then
- 1/ f1 + 1/f2 = 0 ⇒ 1/F = 0 ⇒ F = ∞
- Thus combination behaves as a plane glass plate, not as a lens. So the material should be different so that ω1 ≠ ω2
- If the combination behaves like a convergent lens, then power of convex lens should be greater than the power of concave lens or f1 < f2 hence ω1 < ω2 and therefore the convex lens should be of crown and concave lens should be of flint glass.
- The condition which we use here is only for the elimination of longitudinal chromatic aberration, transverse chromatic aberration can not be removed by it.
- If a number of lenses are combined to form achromatic lens, then
- ω1 / f1 + ω2 / f2 + ω3 / f3 + …= 0 or Σ (ω / f ) = 0
Achromatic combination of two lenses separated by a distance
- If two lenses are separated by a distance d, then the focal length of combination will be
- Since focal length depends on wavelengths
- For achromatism F = constant
- If both lenses are made up of same material, ω1 = ω2 = ω, then
- d = (f1 + f2) / 2
- Since this relation does not contain ω, so the combination has the same value for all the colours.
- Since d never be negative, so (f1 + f2) > 0, hence both the lenses must be either convex or the one with greater focal length must be convex.
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